(5x^2-5x+2)(4-x^2)=0

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Solution for (5x^2-5x+2)(4-x^2)=0 equation: 


Simplifying
(5x2 + -5x + 2)(4 + -1x2) = 0

Reorder the terms:
(2 + -5x + 5x2)(4 + -1x2) = 0

Multiply (2 + -5x + 5x2) * (4 + -1x2)
(2(4 + -1x2) + -5x * (4 + -1x2) + 5x2 * (4 + -1x2)) = 0
((4 * 2 + -1x2 * 2) + -5x * (4 + -1x2) + 5x2 * (4 + -1x2)) = 0
((8 + -2x2) + -5x * (4 + -1x2) + 5x2 * (4 + -1x2)) = 0
(8 + -2x2 + (4 * -5x + -1x2 * -5x) + 5x2 * (4 + -1x2)) = 0
(8 + -2x2 + (-20x + 5x3) + 5x2 * (4 + -1x2)) = 0
(8 + -2x2 + -20x + 5x3 + (4 * 5x2 + -1x2 * 5x2)) = 0
(8 + -2x2 + -20x + 5x3 + (20x2 + -5x4)) = 0

Reorder the terms:
(8 + -20x + -2x2 + 20x2 + 5x3 + -5x4) = 0

Combine like terms: -2x2 + 20x2 = 18x2
(8 + -20x + 18x2 + 5x3 + -5x4) = 0

Solving
8 + -20x + 18x2 + 5x3 + -5x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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